On concentrating the resulting solution, crystals of SnCl2.2H2O
are obtained. When it is heated, basic tin chloride is obtained.
Δ
SnCl2.2H2O(s) ———> Sn(OH)Cl + HCl + H2O
To obtain anhydrous SnCl2
, heat Sn
in dry HCl
gas.
Δ
Sn + 2 HCl ———> SnCl2 + H2
(a) It exists as a anhydrous (white powder, m.p. = 520 K
, rhombic solid) as well as dihydrate
SnCl2.2H2O (white, m.p.
= 480 K, monoclinic) and is used as a strong reducing agent in conc. HCl
in laboratory.
SnCl2 also reduces HgCl2
2HgCl2 + SnCl2 ——> Hg2Cl2 + SnCl4
Hg2Cl2 + SnCl2 ——> 2Hg + SnCl4
(b) It is precipitated as hydroxide by an alkali.
(c) If forms addition compounds with
NH3 such as SnCl2.NH3
and
SnCl2.2NH3. |