Solubility : Halogens, being non polar in nature do not readily dissolve in a polar solvent like water. however, fluorine reacts with water vigorously even at low temperature (exothermally) forming a mixture of ozone and oxygen
2F2 + 2H2O ———> 4 HF + O2
2F2 + 3H2O ———> 6 HF + O3
Chlorine and bromine are fairly soluble but iodine is very little soluble in water. chlorine, bromine and iodine are more soluble in organic solvents like
CCl4.CS2 or
CHCl3 and produce coloured solutions. Thus
Cl2.Br2 and I2
give yellow, brown and violet colour respectively. It is believed that in non-polar solvents, halogens exist as free molecules just as in the gas phase.
In nucleophilic (electron donating) polar solvents like alcohols, ketones or liquid SO2
, halogens produce brown solution. This colour is due to the complex formation (solvent —>
halogen) which are charge transfer compounds.
The solubility of iodine (I2)
in water increases with addition of KI
or NaI
due to the formation of polyhalide (triiodide, I3–
) ion, KI + I2 KI3
However, this solution behaves as a simple mixture of KI and free I2
and contains K+
and I–
ions and free
I2 molecules. It has a brown color. The solution of iodine in water (due to its very little solubility) is also brown.
Oxidizing power : All the halogens acts as strong oxidizing agents since they have a strong tendency to attract electrons and have positive values of electrode potentials
(Eo). The oxidizing power, however, decreases as we move down the group from F
to I
. i.e., F2 > Cl2 > Br2 > I2
Since
F2 is the strongest oxidizing agent, it will oxidize all other halide ions to halogens.
F2 + 2 X– ————> 2 F– + X2 (X = Cl, Br, I)
Similarly,
Cl2 will displace Br–
and
I– ions from their solutions while
Br2 will displace I–
ions only.
Cl2 + 2X– ————> 2Cl– + X2 (X = Br, I)
Br2 + 2I– ————> 2Br– + I2
Hence F2
is the strongest and I2
is the weakest oxidizing agent. This is also indicated by the decrease in the electrode potential (Eo)
for the reaction X2(aq) + 2e– ————> 2X– (aq)
on moving down the group.
The electron affinity of fluorine is less than that of chlorine but still it is the strongest oxidizing agent. This is because of its low bond dissociation energy (158 kJ mol–1)
and high heat hydration (158 kJ mol–1)
as compared to chlorine (for which the values are 243 and 372 kJ mol–1
, respectively). |